Statistics and research

Cronbach’s alpha calculator

Internal-consistency reliability of a scale: Cronbach’s α with Feldt’s confidence interval, standardized α and α-if-item-deleted for each item.

Runs in your browser. What you enter stays on this page and is not uploaded.

Paste the item columns from a spreadsheet. Every line needs the same number of scores.

Results

Cronbach’s α0.955695% CI0.889 to 0.987Items5Respondents10
Cronbach’s α
0.95560213
Standardized α (from correlations)
0.95611822
Mean inter-item correlation
0.813353
95% interval (Feldt)
0.88935 to 0.987401
Sum of item variances
6.8666667
Variance of total scores
29.155556
Item statistics
ItemMeanSDCorrected item–total rα if item deleted
Item 13.41.264910.94880.9323
Item 23.61.074970.83210.9526
Item 33.51.080120.84220.951
Item 43.41.264910.86940.947
Item 53.71.15950.90030.941

α = k/(k − 1) · (1 − Σ item variances / total variance). Reverse-score negatively worded items before pasting.

Method and limits

How to use it

Paste the item scores with one respondent per line and one column per item, straight from a spreadsheet. Reverse-score negatively worded items first, and remove respondents with missing answers.

Formulas

  • α = k/(k − 1) × (1 − Σsi² / sT²), with k items, item variances si² and the variance of the total score sT². It equals Hoyt’s ANOVA reliability 1 − MSresidual/MSpersons.
  • Standardized α = k r̄ / (1 + (k − 1) r̄), from the mean inter-item correlation r̄.
  • Feldt’s interval: (1 − α)/(1 − α̂) follows F(n − 1, (n − 1)(k − 1)), giving 1 − (1 − α̂)F1−γ/2 to 1 − (1 − α̂)Fγ/2.
  • Corrected item–total correlation: each item against the sum of the other items; α if item deleted recomputes α without it.

Assumptions and limits

  • α measures internal consistency, not that the scale measures one thing; a long scale can have a high α with several dimensions.
  • It assumes items measure the same trait on the same scale (tau-equivalence); otherwise it underestimates reliability (consider McDonald’s ω).
  • Rules of thumb (0.7 acceptable, 0.8 good, 0.9 excellent) depend on the use; above 0.95 may signal redundant items.

Worked example

The example has 10 respondents and 5 items. The item variances sum to 6.867 and the total-score variance is 29.156, so α = 5/4 × (1 − 6.867/29.156) = 0.956, with a 95% Feldt interval of 0.889 to 0.987.

References

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